A conversation between User and Assistant. The user asks a question, and the Assistant solves it. The assistant first thinks about the reasoning process in the mind and then provides the user with the answer.
User: A very special island is inhabited only by knights and knaves. Knights always tell the truth, and knaves always lie. You meet 7 inhabitants: Mason, Abigail, James, Elizabeth, Jacob, Chloe, and Riley. Mason told you that If Jacob is a knight then Elizabeth is a knave. Abigail expressed that Jacob is a knave and Mason is a knight. "Abigail is not a knave," James claimed. According to Elizabeth, "Mason is a knight". Jacob commented, "Mason is a knight if and only if Abigail is a knave". Chloe asserted: "James is a knave or Abigail is a knight". Riley commented, "Mason is a knight or Riley is a knight". So who is a knight and who is a knave? Show your work in <think> </think> tags. And return the final answer in <answer> </answer> tags, for example <answer> (1) Zoey is a knight
(2) Oliver is a knight
(3)... </answer>.
Assistant: Let me solve this step by step.
<think> 
user
Assume Mason is a knight.  No contradiction is found in their claim that If Jacob is a knight then Elizabeth is a knave.
 Assume Jacob is a knight.  No contradiction is found in their claim that Mason is a knight if and only if Abigail is a knave.
 Abigail cannot be a knight, because this would contradict the claim of their own that Jacob is a knave and Mason is a knight.
 Assume Abigail is a knave.  No contradiction is found in their false claim that Jacob is a knave and Mason is a knight.
 Elizabeth cannot be a knight, because this would contradict the claim of Mason that If Jacob is a knight then Elizabeth is a knave.
 Elizabeth cannot be a knave, because this would contradict the false claim of their own that Mason is a knight.
 We have exhausted all possibilities for Elizabeth and Abigail, so let us go back and reconsider Jacob.
 Assume Jacob is a knave.  No contradiction is found in their false claim that Mason is a knight if and only if Abigail is a knave.
 Assume Abigail is a knight.  No contradiction is found in their claim that Jacob is a knave and Mason is a knight.
 Assume Elizabeth is a knight.  No contradiction is found in their claim that Mason is a knight.
 Assume James is a knight.  No contradiction is found in their claim that Abigail is not a knave.
 Assume Chloe is a knight.  No contradiction is found in their claim that James is a knave or Abigail is a knight.
 Assume Riley is a knight.  No contradiction is found in their claim that Mason is a knight or Riley is a knight.
 Therefore, (1) Mason is a knight
 (2) Abigail is a knight
 (3) James is a knight
 (4) Elizabeth is a knight
 (5) Jacob is a knave
 (6) Chloe is a knight
 (7) Riley is a knight
A conversation between User and Assistant. The user asks a question, and the Assistant solves it. The assistant first thinks about the reasoning process in the mind and then provides the user with the answer.
User: A very special island is inhabited only by knights and knaves. Knights always tell the truth, and knaves always lie. You meet 7 inhabitants: Mason, Abigail, James, Elizabeth, Jacob, Chloe, and Riley. Mason told you that If Jacob is a knight then Elizabeth is a knave. Abigail expressed that Jacob is a knave and Mason is a knight. "Abigail is not a knave," James claimed. According to Elizabeth, "Mason is a knight". Jacob commented, "Mason is a knight if and only if Abigail is a knave". Chloe asserted: "James is a knave or Abigail is a knight". Riley commented, "Mason is a knight or Riley is a knight". So who is a knight and who is a knave? Show your work in <think> </think> tags. And return the final answer in <answer> </answer> tags, for example <answer> (1) Zoey is a knight
(2) Oliver is a knight
(3)... </answer>.
Assistant: Let me solve this step by step.
<think> 
Assume Mason is a knight. No contradiction is found in their claim that If Jacob is a knight then Elizabeth is a knave.
Assume Jacob is a knight. No contradiction is found in their claim that Mason is a knight if and only if Abigail is a knave.
Abigail cannot be a knight, because this would contradict the claim of their own that Jacob is a knave and Mason is a knight.
Assume Abigail is a knave. No contradiction is found in their false claim that Jacob is a knave and Mason is a knight.
Elizabeth cannot be a knight, because this would contradict the claim of Mason that If Jacob is a knight then Elizabeth is a knave.
Elizabeth cannot be a knave, because this would contradict the false claim of their own that Mason is a knight.
We have exhausted all possibilities for Elizabeth and Abigail, so let us go back and reconsider Jacob.
Assume Jacob is a knave. No contradiction is found in their false claim that Mason is a knight if and only if Abigail is a knave.
Assume Abigail is a knight. No contradiction is found in their claim that Jacob is a knave and Mason is a knight.
Assume Elizabeth is a knight. No contradiction is found in their claim that Mason is a knight.
Assume James is a knight. No contradiction is found in their claim that Abigail is not a knave.
Assume Chloe is a knight. No contradiction is found in their claim that James is a knave or Abigail is a knight.
Assume Riley is a knight. No contradiction is found in their claim that Mason is a knight or Riley is a knight.
Therefore, (1) Mason is a knight
(2) Abigail is a knight
(3) James is a knight
(4) Elizabeth is a knight
(5) Jacob is a knave
(6) Chloe is a knight
(7) Riley is a knight </think>
<answer> (1) Mason is a knight
(2) Abigail is a knight
(3) James is a knight
(4) Elizabeth is a knight
(5) Jacob is a knave
(6) Chloe is a knight
(7) Riley is a knight </answer>
Mason Abigail James Elizabeth Jacob Chloe Riley
(1) Mason is a knight
(2) Abigail is a knight
(3) James is a knight
(4) Elizabeth is a knight
(5) Jacob is a knave
(6) Chloe is a knight
(7) Riley is a knight
(('->', ('telling-truth', 4), ('lying', 3)), ('and', ('lying', 4), ('telling-truth', 0)), ('not', ('lying', 1)), ('telling-truth', 0), ('<=>', ('telling-truth', 0), ('lying', 1)), ('or', ('lying', 2), ('telling-truth', 1)), ('or', ('telling-truth', 0), ('telling-truth', 6)))
rule