User edited file: "lc0049_group_anagrams.py":

```diff
@@ -19,7 +19,7 @@
 - The order of your output does not matter.
 """
 
-class SolutionSortedDict(object):
+class SolutionSortedAnagramDict(object):
     def groupAnagrams(self, strs):
         """
         :type strs: List[str]
@@ -57,4 +57,4 @@
 
 
 if __name__ == '__main__':
-    main()
+    main()
```

User edited file: "lc0049_group_anagrams.py":

```diff
@@ -35,14 +35,14 @@
         from collections import defaultdict
 
         # Store in a dict with sorted string->string list.  
-        anagrams_d = defaultdict(list)
+        anagram_lists = defaultdict(list)
 
         for s in strs:
             # Use sorted string as dict key.
             k = ''.join(sorted(s))
-            anagrams_d[k].append(s)
+            anagram_lists[k].append(s)
 
-        return anagrams_d.values()
+        return anagram_lists.values()
 
 
 def main():

```
```lc0049_group_anagrams.py
"""Leetcode 49. Group Anagrams
Medium

URL: https://leetcode.com/problems/group-anagrams/

Given an array of strings, group anagrams together.

Example:
Input: ["eat", "tea", "tan", "ate", "nat", "bat"],
Output:
[
  ["ate","eat","tea"],
  ["nat","tan"],
  ["bat"]
]

Note:
- All inputs will be in lowercase.
- The order of your output does not matter.
"""

class SolutionSortedAnagramDict(object):
    def groupAnagrams(self, strs):
        """
        :type strs: List[str]
        :rtype: List[List[str]]

        Output Limit Exceede.

        Time complexity: O(n*klogk), where
          - n is the length of strs,
          - k is the lenght of the longest string.
        Space complexity: O(n).
        """
        from collections import defaultdict

        # Store in a dict with sorted string->string list.  
        anagram_lists = defaultdict(list)

        for s in strs:
            # Use sorted string as dict key.
            k = ''.join(sorted(s))
            anagram_lists[k].append(s)

        return anagram_lists.values()


def main():
    # Output:
    # [
    #   ["ate","eat","tea"],
    #   ["nat","tan"],
    #   ["bat"]
    # ]
    strs = ["eat", "tea", "tan", "ate", "nat", "bat"]
    <|user_cursor_is_here|>
    print SolutionSortedDict().groupAnagrams(strs)


if __name__ == '__main__':
    main()
```
```lc0049_group_anagrams.py
"""Leetcode 49. Group Anagrams
Medium

URL: https://leetcode.com/problems/group-anagrams/

Given an array of strings, group anagrams together.

Example:
Input: ["eat", "tea", "tan", "ate", "nat", "bat"],
Output:
[
  ["ate","eat","tea"],
  ["nat","tan"],
  ["bat"]
]

Note:
- All inputs will be in lowercase.
- The order of your output does not matter.
"""

class SolutionSortedAnagramDict(object):
    def groupAnagrams(self, strs):
        """
        :type strs: List[str]
        :rtype: List[List[str]]

        Output Limit Exceede.

        Time complexity: O(n*klogk), where
          - n is the length of strs,
          - k is the lenght of the longest string.
        Space complexity: O(n).
        """
        from collections import defaultdict

        # Store in a dict with sorted string->string list.  
        anagram_lists = defaultdict(list)

        for s in strs:
            # Use sorted string as dict key.
            k = ''.join(sorted(s))
            anagram_lists[k].append(s)

        return anagram_lists.values()


def main():
    # Output:
    # [
    #   ["ate","eat","tea"],
    #   ["nat","tan"],
    #   ["bat"]
    # ]
    strs = ["eat", "tea", "tan", "ate", "nat", "bat"]
    <|tool_call|>
    {"name": "refactor.rename", "arguments": {"symbol": "SolutionSortedDict", "newName": "SolutionSortedAnagramDict"}}
    </|tool_call|>
    print SolutionSortedDict().groupAnagrams(strs)


if __name__ == '__main__':
    main()
```