On the other hand, we analyze the requirement of the first term that (1 − cγ) t (a 0 − a ∞ ) ≤ ϵ q .
since a 0 − a ∞ ≤ a 0 , it holds by requiring (1 − cγ) t a 0 ≤ ϵ q , which goes to since log (1 − cγ) ≤ −cγ given 7, and that log ϵ qa 0 is a negative term, we have setting t .