In this case, it is important to remember that w 1 has a false friend w 2ff , so we know that accessing w 2 is more effortful since, for a bilingual speaker, w 2ff will also be activated.
we can assume that a normal pair of words (w 1n , w 2n ), a pair of translated words that have no false friend, are closer in space than (w 1 , w 2 ) precisely because (w 1n , w 2n ) is not inhibited by a false translation as in the case of (w 1 , w 2 ).