With an exponential prior, we maximize As we will describe, it is significantly simpler to perform this maximization than the Gaussian maximization.
furthermore, as we will describe, models satisfying Equation 2 will have the property that, for each λ i , either a) λ i = 0 and we essentially just discount the observed counts by the constant α i (which is the reciprocal of the standard deviation), subject to the constraint that λ i is non-negative.