Then using the discounting scheme described, we have P(damnbritish) = 1/(x + 6) P(damn) = 2/(x+6) P(british) = x/(x + 6) and We seek an x for which P(damn)P(british) > P(damnbritish).
as we argued, the permutation and averaging does have significant beneficial side effects, and if anything, it only eliminates from the point of view of the algorithms the important advantage that real children may be given by their mothers through a specific ordering of the utterances.